Multi-Dimensional Arrays - stuck on code

Question

You are a movie theater manager.
You are given a two-dimensional array with 6 rows and 6 columns - 36 elements with 0 value, that represent empty theater seats.
All 36 tickets for session were sold, so you need to identify all of the seats with value 1.
Write a program that replaces all 0 values in the given array by 1 and outputs the resulting matrix.

All I got is change 0 to 1 in the first column. How do I do the rest?

https://www.sololearn.com/learning/1051/1629/2857/1

Answer 1

for (int rows = 0; rows < 6; rows++) {
for (int cols = 0; cols < 6; cols++) {
cout << matrix[rows][cols] + 1;

also works. Is one better than the other as far as functionality?

Answer 2

Thanks

Answer 3

import numpy as np

data = np.array([1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, 0])

row = int(input())
data = data.reshape(6,5)
print(data[row])

Answer 4

#include <iostream>
using namespace std;

int main() {

string arr[3][3] = {
{"Python", "JS", "C++"},
{"PHP", "SQL", "Java"},
{"C#", "Swift", "Kotlin"},
};
// your code goes here
cout<<arr[0][2]<<endl;
return 0;
}

Good Luck

Answer 5

#include <iostream>
using namespace std;

int main() {

int rows = 6;
int cols = 6;

float matrix[rows][cols] = {
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 0},
};

// your code goes here
for (int rows = 0; rows < 6; rows++) {
for (int cols = 0; cols < 6; cols++) {
cout << matrix[rows][cols] + 1;
}
}
return 0;
}

Good Luck

Answer 6

#include <iostream>
using namespace std;

int main() {

string arr[3][3] = {
{"Python", "JS", "C++"},
{"PHP", "SQL", "Java"},
{"C#", "Swift", "Kotlin"},
};
// your code goes here
cout<<arr[0][2]<<endl;
return 0;
}

Answer 7

int i, j;

for (i = 0; i < rows; i++){
for (j = 0; j < cols; j++){
matrix[i][j] = 1;
cout << matrix[i][j] << endl;
}
}

Answer 8

agree with the options above. but I would add if function.

// your code goes here
for (int x=0; x<rows;x++){
for(int y=0; y<cols;y++)
{
cout << matrix[rows][cols]+1;
if(y>4)
cout << endl;
}

}