How can multiple keys have a value?

Question

Example :

# Just a small example don't try to debug this, I want to not use "if"
Inp = int(input())
dic = {
'''Inp between 1 and 9''' : "One digit",
'''Inp between 10 and 99''' : "Two digit"
}
Print (dic[Inp])

Answer 1

https://code.sololearn.com/cBUny24kf4c7/?ref=app

Swift edit: update to onelined print (initial code commented)

Answer 2

your question is unclear...
try to be more descriptive, and/or provide real code ^^

Answer 3

no, range objects are not valid keys, and even if it was, bmi is not a range but a number ^^

I undestand that you try to emulate a 'switch' statement (not available in python): there could be possible to do such things, but I think you have to deal with 'if' as alternative solutions must be a little bit more tricky ;)

Answer 4

even with a switch statement, you couldn't use range ^^

for a bunch of ranges to be tested, you should use a structure combining a range and a function at each item, iterate over it and testing value against range... if test return true you can use the return value of the associated function ;)

Swift edit:

you could associate just a value instead of a function, obviously...

Answer 5

madeline the code is just an example, i could make it WAAAY easier :

https://code.sololearn.com/c38g46aS5n3u/?ref=app

Answer 6

Swift so did you figure it out?

Answer 7

madeline I wanted to know if i can replace "if" with dictionaries in all cases.
Sadly there is no way in Python

Answer 8

in fact, python3 accept range as keys (in python2 you should use xrange to get immutable)...

anyway:

1) you cannot define range with float, only integer boundaries

2) you should iterate over dict keys and check if value is in range, as accessing a dict with ranges as keys would not have values for numerical keys (unless you define some): key error will be raised...

Answer 9

visph one of the practice codes by sololearn which is a bmi calculator :

w = int(input())
h = float(input())
bmi = w/(h**2)

dic = {
range(18.5) : "Underweight",
range(18.5,25) : "Normal",
range(25,30) : "Overweight",
range(30,100) : "Obesity"
}
print(dic[bmi])

Answer 10

visph thanks, if is hard in more situations (over 10 possibilities)

but there is nothing that i can do