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[SOLVED] Can someone show me how char works

I'm trying to do the lessons 7.1 on Java called Computer Speak, where a user inputs a letter and I have to print it out as a number, but I don't understand how char works so my code won't work import java.util.Scanner; class Main { public static void main(String[] args) { Scanner read = new Scanner(System.in); String[] char a =read.next().charAt(0); int count=97; for(int i=0;i!=25;i++) { if(char a[i]==a) { char.replace[i]==count; } System.out.println(char[i]); count++; } //your code goes here }

1st Mar 2021, 6:33 PM
Serana Zentha
Serana Zentha - avatar
9 Respuestas
+ 3
char[] a will declare character array , not single character and you cant assign single character by that way.. Just do char a = read.next().charAt(0); and if(a='a'||'A') will assign 'a' in a. And it returns always true. if you are trying about checking a have 'a' or 'A' then it must be like if( a== 'a' || a== 'A' ) Edit: Serana Zentha after removing error in your above updated code ,it just prints a space if 'if clouse is true' otherwise nothing..
1st Mar 2021, 7:22 PM
Jayakrishna 🇮🇳
+ 3
Character declaration is just like : ex: char a='a'; so you just need char ch=read.next().charAt(0); This will read a word but take only a charecter at index 0. and assign it into charecter variable ch. You have wrong syntax in if condition. To print it as a number, print its ascii value by casting it to int type as System.out.println( (int)ch);
1st Mar 2021, 6:47 PM
Jayakrishna 🇮🇳
+ 2
Post your updated code.. String[] char a =read.next().charAt(0); if(char a[i]==a) char.replace[i]==count; These 3 lines have wrong syntaxes.. Not valid statements. If you checking 'a' then it must be if(a == 'a') About 3rd => i dont understand what you tried there..
1st Mar 2021, 7:09 PM
Jayakrishna 🇮🇳
+ 1
Jayakrishna🇮🇳 i keep getting no output, no matter how I try to print it or cast it. it won't let me cast it
1st Mar 2021, 7:03 PM
Serana Zentha
Serana Zentha - avatar
+ 1
Jayakrishna🇮🇳 im trying to print a letter as a number by casting but i have no idea what this lesson even wants me to do as it throws char in my fave despite the fact I have no idea what char even does
1st Mar 2021, 7:10 PM
Serana Zentha
Serana Zentha - avatar
+ 1
Jayakrishna🇮🇳 I tried doing something simple just to print char a but this wint print either, I have no idea what I'm doing i dont know how my syntax is wrong because i don't use char to begin with, could you please explain why my syntax is wrong, I know it's wrong but I don't know why I don't use char at all import java.util.Scanner; class Main { public static void main(String[] args) { Scanner read = new Scanner(System.in); char[] a = read.next().charAt(0); for(int i=0;i!=25;i++) { if(a='a'||'A') { System.out.println(" "); } }
1st Mar 2021, 7:14 PM
Serana Zentha
Serana Zentha - avatar
+ 1
Jayakrishna🇮🇳 thank you ill let you know if it works
1st Mar 2021, 7:22 PM
Serana Zentha
Serana Zentha - avatar
+ 1
Jayakrishna🇮🇳 it worked thank you soooo much i was starting to lose my mind
1st Mar 2021, 7:26 PM
Serana Zentha
Serana Zentha - avatar
+ 1
//sample code for casting.., check this once if you need.. import java.util.Scanner; public class Program { public static void main(String[] args) { Scanner in = new Scanner(System.in); char ch=in.next().charAt(0); System.out.print((int)ch); } } //Edit: Serana Zentha you're welcome..
1st Mar 2021, 7:29 PM
Jayakrishna 🇮🇳