+ 5

Can u use for loop here (python dictionary problem)[SOLVED]

x=input() car = { 'brand':'BMW', 'year': 2018, 'color': 'red', 'mileage': 15000 } if (x=='year'): print(car['year']) elif x=='color': print(car['color']) elif x=='mileage': print(car['mileage']) elif x=='brand': print(car['brand'])

19th Mar 2021, 2:27 PM
Goku
Goku - avatar
20 Respuestas
+ 8
you could use loop for this task, but the more pythonic way would be to use dict.get(key) method ;)
19th Mar 2021, 2:33 PM
visph
visph - avatar
+ 6
You in no way need a loop, but here. https://code.sololearn.com/cxsxz91F8iaq/?ref=app
19th Mar 2021, 2:38 PM
Slick
Slick - avatar
+ 6
key = input() car = { 'brand':'BMW', 'year': 2018, 'color': 'red', 'mileage': 15000 } for k, v in car.items(): if k==key: print(v) ... or few shorter (but onelined): print(next(v for k, v in car.items if k==key))
19th Mar 2021, 2:43 PM
visph
visph - avatar
+ 6
Goku , Yes, you can surely use for loops. Everyone has already shown above 👆 how it can be solved in different ways using for loops.
19th Mar 2021, 3:16 PM
Shivani 📚✍
Shivani 📚✍ - avatar
+ 4
Goku Yes you can use loop even you can directly get the value by just passing key as car is a dictionary. See this -------1st way------ for i in car: if i == x: print (car[i]) -------2nd way-------- print (car[x])
19th Mar 2021, 2:38 PM
A͢J
A͢J - avatar
+ 4
Slick You can also iterate dictionary like this for key in car: print (key) So here input can be compare with key but not with key: value pair as you said
19th Mar 2021, 2:50 PM
A͢J
A͢J - avatar
+ 4
Goku, As others have mentioned, use of loop is possible, but its necessity should be considered thoroughly. For example, if you want to print the key-value pairs from dictionary <car> you can do for ( key, value ) in car.items(): print( f"{key} : {value}" ) But if you only want to output one of the pairs (if any match), you can use subscript operator [], or use `get()` method https://www.w3schools.com/JUMP_LINK__&&__python__&&__JUMP_LINK/ref_dictionary_get.asp
19th Mar 2021, 2:53 PM
Ipang
+ 3
Your program needs to take the key as input and output the corresponding value. Sample Input: year Sample Output: 2018 Question ☝️
19th Mar 2021, 2:28 PM
Goku
Goku - avatar
+ 3
Shivani 📚✍ [Exams] I got the output using if ..but can we add loop in this task
19th Mar 2021, 2:32 PM
Goku
Goku - avatar
+ 3
Goku, Why you think we need a loop there? I don't get why we need a loop though;
19th Mar 2021, 2:35 PM
Ipang
+ 3
Ipang I just want to know that we can use loop or not
19th Mar 2021, 2:37 PM
Goku
Goku - avatar
+ 3
🅘🅜 🅰🅹 !!! the input is a string and that code would comapre a string to a dict key:value pair. You could do car.keys() tho
19th Mar 2021, 2:40 PM
Slick
Slick - avatar
+ 3
Slick Well keys are also string so no problem here
19th Mar 2021, 2:44 PM
A͢J
A͢J - avatar
+ 1
car = {...} x = input() # ~~~ Method 1: print(x.get(x, "\0")) # ~~~ Method 2: if x in car: print(car[x]) # ~~~ Method 3 (slow): [print(car[y]) for y in car if x == y] # Hope this helps
20th Mar 2021, 3:05 PM
Calvin Thomas
Calvin Thomas - avatar
0
Alot of ways we can use it, but the way you do is important.
20th Mar 2021, 3:20 PM
Jyothiswaroop.K
Jyothiswaroop.K - avatar
0
car = {'brand':'BMW', 'year': 2018, 'color': 'red', 'mileage': 15} key = input() print(car[key])
6th Nov 2021, 7:16 AM
Aayush Shrivastava
Aayush Shrivastava - avatar
- 3
I prefer to use switch instead if elif
20th Mar 2021, 7:21 AM
Ikram Arshad
Ikram Arshad - avatar
- 3
hi
22nd Mar 2021, 5:39 AM
Aungkoko
Aungkoko - avatar
- 4
kelar kan komentat
21st Mar 2021, 1:28 PM
Syamri Icam
Syamri Icam - avatar
- 4
deled
21st Mar 2021, 1:29 PM
Syamri Icam
Syamri Icam - avatar