Elif Statement Challenge question

Question

Been having an issue with the Elif statement V challenge

write a program that takes a number as input and:
returns it’s double if the number is even
returns its triple if odd
Returns 0 if 0

The code I’ve been trying to use is this:

number = input()
if number % 2 == 0:
print(number * 2)
elif number % 2 != 0:
print(number * 3)
elif number == 0:
print(0)

The output keeps returning with the error “not all arguments converted during string formatting” for Line 2. Not sure what my misstep here is?

Answer 1

U have to specify the input as int,like this:

number = int(input())
if number % 2 == 0:
print(number * 2)
elif number % 3 == 0:
print(number * 3)
elif number == 0:
print(0)

oh and i changed the line number 4

Answer 2

https://code.sololearn.com/cHoWIV3L15Y9/?ref=app

This may help you!

Answer 3

Much appreciated! int(input()) fixed it

Answer 4

n = int(input())
if n%2 == 0:
print(2*n)
elif n%2 != 0:
print(3*n)
elif n == 0:
print(0)