Geometric progression

Question

Given the second and third terms (-2.0 <=g2, g3 <= 2.0) of a GP, find the nth (1 <= n <= 100) term. The output should be a string representing the Inth term, rounded off to 3 decimal places.

You are required to fill in a function which takes as input an integer 'n' and sets the output variable to the sum of divisors of 'n'. The output is to be guaranteed to fit in a 32-bit signed integer.

Input Specification:

input1: Second Term of GP (Double) input2: Third Term of GP (Double)

input3: Total number of terms in the series (Int)
Output Specification:

Return a string representing the nth term, rounded off to 3 decimal places.

Example 1:

input1: 1

input2: 2

input3: 4

Output: 4.0

Explanation:

g2= 1, g3 = 2, n = 4, r = 2, gn = g4 = 4 (r refers to the common ratio between adjacent terms in a geometric progression)
Example 2:

input1: 1

input2: 2

input3: 5

Output: 8.0

Explanation:

g2= 1, g3 = 2, n = 5, r = 2, gng4 = 8 (r refers to the common ratio between adjacent terms in a geometric progression)

Answer 1

#include<stdio.h>

#include<string.h>

// Read only region start

char* nthTerm(double input1, double input2, int input3) {

// Read only region end

// Write code here

double r = input2/input1; double ans = a* (double) pow(r, (double) (input3-1));

double a input1/r;

char result = new char[1000];

Results

Your Testcase

on ratio

}
This is my code can any find the error in that code