how can I round this code up?

Question

houses = int(input())
#your code goes here
print(int(100.5/houses+0.5)*2)

I am solving an easy community problem called Hallowen sweets and I am already desperate because that damn one skips the number I need, if the input is 3 it comes out 66 or 68, not the correct number

Answer 1

import math
houses = int(input())
doll=2
t=float(doll/2)
c=float(houses/2)
p=int(math.ceil(doll*100/houses))
print(p)

#Are you telling about this math.ceil function?

Answer 2

There are a couple of ways.

#Write your own
num1 = 7
num2 = 2

result = num1 // num2
print(result) #3

if num1 % num2 != 0:
result += 1
print(result) #4

# or use import math.ceil()

import math
print(math.ceil(num1 / num2)) #4

Answer 3

Here's a quick implementation of math.ceil() :

# The integer

a = 56

# a = math.ceil(a)

a = int(a) + (a > int(a))