tell me how to make sure that when the array element reaches Saturday, the array starts repeating again

Question

let dayWeek = new Date();
let days = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'];
let d = new Date().getDay()
let choose = confirm('Want to see the next day?');
while (choose == true) {
alert(days[d])
d++;
let choose = confirm('Want to see the next day?');
if (choose == false) {
break;
}
}

Answer 1

Just add an if statement that checks if d is greater than or equal to the last index + 1 (length) and sets d to 0 if true.

Answer 2

//Thank you all, I did it so
let dayWeek = new Date();
let days = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday'];
let d = new Date().getDay()
alert("Today is " + days[d]);
let choose = confirm('Want to see the next day?');
while (choose == true) {
d++;
alert(days[d])
if (d >= 6) {
d = -1;
}
let choose = confirm('Want to see the next day?');
if (choose == false) {
break;
}
}

//Everything seems to be working))

Answer 3

i believe you need a if statement where d++ is. if d is greater than or equal to 6, set d equal to 0. an example of a shorthand (ternary) conditional if statement is provided below:

d >= 6 ? d = 0: d++;

or if you prefer:

if (d >= 6) {
d = 0
} else {
d++
};

Answer 4

Andrew Choi
Your ternary should be like;
d = d >= 6 ? 0 : ++d;

Using an if statement could be a few different ways depending on where you use d++ or ++d.

d++
if (d >= 7)
d = 0;

if (++d >= 7)
d = 0;

if (d++ >= 6)
d = 0;

Etc.

Answer 5

ChaoticDawg i appreciate the input. looks like either options will work.

Answer 6

Martin Taylor too true. Lol and a very common solution.
Sometimes, I just use the K.I.S.S. method instead for the question, so I don't need to explain my previous explanation.