Why do i keep getting an overload error every time i run this?

Question

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt();
//your code goes here
while (number >= 0 ){

if(number%3==0){
continue;
}
System.out.println(number--);

}
}
}
The question is : Write a program that takes N numbers as input and outputs the numbers from N to 0, skipping the ones that are multiples of 3.

I dont know how else to write this or even why there is an error.

From what i understand the code says:
While the number is great than or equal to 0 check if the number is a multiple of "3" by dividing the number by 3 and seeing if the remainder is 0.
If the remainder is not 0 leave this statement.
print out on a new line number - 1.

can someone explain my error?

Answer 1

Your problem is "continue".

Continue means do nothing and just go on with the loop (ignore the rest after continue). Means in your case:

number % 3 gets true
-> continue
-> jump to the head of your loop
-> check condition (is true because nothing happend to number)
-> number % 3 is true
-> continue
and so on...

Using continue inside a for loop is no problem, because normally you incrment/decrement your variable in the head of the loop.

e.g.
for(int i = 0; i <= 10; i++){

if(i % 3 == 0) continue;

}

-> continue -> head of the loop and here i gets incremented

In your while loop if you want to use continue you can do this:

if(number % 3 == 0){

number--;
continue;

}

Answer 2

@Denise Roßberg
Thank you that makes a lot of sense.

Answer 3

Change == with !=, put the println in the then branch and remove the else branch. Number-- goes outside the if