+ 1

Why this code not working properly for value pairs like 5 , 1 and 3

https://code.sololearn.com/cTnsKpM5Mhwf/?ref=app Here in this code when I give a value which tend to solve for imaginary roots it donot work completely perfect . Always value of variable root1real and rootreal2 is zero.

22nd Apr 2021, 5:41 AM
Vijay Gunwant
Vijay Gunwant - avatar
4 Respuestas
+ 1
#include <iostream> #include<cmath> using namespace std; int main() { cout<<"Enter Coffecient Of x^2 :"; int a; cin>>a; if (a == 0) { cout<<"Coffecient of x^2 can't zero"; } else { cout<<"\nEnter Coffecient Of x :"; int b; cin>>b; cout<<"\nEnter Constant Term :"; int c; cin>>c; int d = (b * b) - (4 * a * c); if (d >= 0) { double root1 = ((- b) + sqrt(d))/(2.0 * a); double root2 = ((- b) - sqrt(d))/(2.0 * a); cout<<"\nRoot1 = "<<root1; cout<<"\nRoot2 = "<<root2; } else { d *= -1; double root1real = (- b)/(2.0 * a); double root2real = (- b)/(2.0 * a); double root1img = (sqrt(d))/(2.0 * a); double root2img = (sqrt(d))/(2.0 * a); cout<<"\nRoot1 = "<<root1real<< " + "<<root1img<<"i"; cout<<"\nRoot2 = "<<root2real<<" - "<<root2img<<"i"; } } }
22nd Apr 2021, 5:47 AM
RKK
RKK - avatar
+ 2
In your code: (- b)/(2 * a) b was integer a was integer when you multiply/divide etc an integer by another integer you get integer(that is 2*a = integer) But to get a correct answer, we need our denominator to be of decimal type and therefore by making 2 or 'a' a double or float type solved the problem. (- b)/(2.0 * a) or (- b)/(2 * a*1.0) would work. Because integer/double equals to double.
22nd Apr 2021, 5:58 AM
RKK
RKK - avatar
+ 2
Rohit thank you now I got it
22nd Apr 2021, 7:18 AM
Vijay Gunwant
Vijay Gunwant - avatar
+ 1
Rohit thankyou very much . But can you Explain me how by making 2 to 2.0 corrected the problem
22nd Apr 2021, 5:51 AM
Vijay Gunwant
Vijay Gunwant - avatar