Write a program which takes input as integer only that is restrict other characters​ form​ inputs ?

Question

c++ program which is important for a good programmer.

Answer 1

int main()
{
int x;

while (!(cin >> x))
{
cin >> x;
cin.clear(); cin.ignore(512, '\n');
}

cout << "You entered : " << x;

return 0;
}

Answer 2

What do you mean by removing one digit?

Answer 3

Please refer
https://code.sololearn.com/cvbzeX3s8MN7/#cpp
Try it on your PC as it may not work on Playground

Answer 4

#include<iostream.h>
#include<conio.h>
int getintegerOnly();
int main()
{
int x=0;
clrscr();
x=getintegerOnly();
cout<<"/n you have "<<x;
getch();
return 0;
}
int getintegerOnly()
{
int num=0;char ch;
do
{
ch=getch();
if(ch>=48&&ch<=57)
{
cout<<ch;
num=num*10+(ch-48);
}
if(ch=='\b')
{
clrscr();
num=num/10;
cout<<num;
}
if(ch==13)
{
return(num);
}}while(1);}

Answer 5

suppose first input 1 and second input 2 and third input 3 then we can see 123 on console screen but we want to remove 3 (last digit of number) on Console screen then output 12 . if want to remove again last digit then output 1.

Answer 6

if we want to removing one digit on Console screen when what do you do?

Answer 7

Great! But I have a doubt whether clrscr () function is supported by current C++ version

Answer 8

Then hats off to you I tried the same way back in 1995, hard to recall.

Answer 9

Make a little change - use getche () instead of getch (). You will see the difference.

Answer 10

no sir but my answers according to turbo c++

Answer 11

yes sir but we want to taking only integers value according to question .when we use getche() we can takes character and integers so we can use getch().