Can you tell me the reason behind the output?

Question

#include<stdio.h>
int main()
{
int c=0;
if(c=0)
printf("%d",c=0);
else
printf("%d",c=1);
printf("%d\n",c);
}

Answer 1

So I guess the output is 11?
You assigned 0 to c, so 'if(c=0)' is false , cuz 0 returns false.
You are not checking if c is equal to zero, but you are trying to assign 0 to c. Try c==0 to compare.

So when your if does not execute, you jump to 'else' printing this c=1 (is output 1 or 0?).

Then you go out of 'else' and print 1, as you assigned 1 to c in previous printf

Answer 2

Assignment operator(=) operates by assigning the value on left hand side to the variable on right hand side and returns the value it just assigned.

In your case

"if(c = 0)" will evaluate to "if(0)" which is false so the control goes in else part where "printf("%d",c=1)" tells your system to assign value 1 to the variable "c" and print it on the screen.

Outside it, the second printf() is just printing the current value in variable "c" which is 1.

Thus the output would be
11

Answer 3

Thanks Arsenic