Binary Converter

Question

The binary numeric system uses only two digits: 0 and 1. Computers operate in binary, meaning they store data and perform calculations using only zeros and ones.

You need to make a program to convert integer numbers to their binary representation.
Create a Converter class with a static toBinary() method, which returns the binary version of its argument.
The code in main takes a number as input and calls the corresponding static method. Make sure the code works as expected.

Sample Input:
42
Sample Output:
101010

You can use the following code to convert a number to binary:

import java.util.Scanner;

//your code goes here
String binary="";
while (num > 0) {
binary = (num%2)+binary;
num /= 2;
}

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.print(Converter.toBinary(x));
}
}
Here's the code that I have so far. What do i do from this point?

Answer 1

//your code goes here
public class Converter {
public static String toBinary(int n) {
String output = "";
if (n >= 1) {
output = toBinary(n >> 1) + (n % 2);
}

return output;
}

}

Answer 2

public class Converter {
public static String toBinary(int n) {
String output = "";
if (n >= 1) {
output = toBinary(n >> 1) + (n % 2);
}

return output;
}

}

Answer 3

ok ok ok:

import java.util.Scanner;

public class Converter {
public static String toBinary(int num) {
String binary="";
while(num > 0) {
binary = (num%2)+binary;
num /= 2;
}
return binary;
}
}

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.print(Converter.toBinary(x));
}
}

Answer 4

From 'Converter.toBinary(x)', we can tell that this process should be executed from a method toBinary(int) which is from a class or an object called Converter.

Converter as a class looks more natural as it is capital and easier to do for this code.

That means you have to create a Converter class with one static method String toBinary(int num) and put your implementation in the method. Remember to return binary at the end of the code.

Answer 5

Here is my code:

def convert(num):
if num==1:
return "1"

else:
return (str(int(num) % 2) + str(convert(int(num) // 2)))

a=convert(input())
print(a[len(a)::-1])