How do I solve this pls 🙏

Question

So I studied the filter function and I'm trying to return the FALSE part too. For example

def pass_grades(grades):
return grades > 50
scores = [10,30,50,70,22, 90]
passers = list(filter(pass_grades(scores)
print(passers)

The output will be all pass grades in a list. But what If I want to return pass grade in one list and also failed grades in another list

Answer 1

Elijah Nwalozie ,

this task can be done with filter as you can see in the attached code. instead of using a regular function in filter(), it is easier to use a lambda function to solve this task.
https://code.sololearn.com/cgPGjI9UbQfy/?ref=app

Answer 2

`filter` is used to sort out stuffs that doesn't match a criteria from an iterable. I don't think it makes sense to use `filter` to split contents of an iterable.

If you want to separate the ones who pass from those who fails, then you can prepare 2 extra `list` objects into which you will append stuffs as you iterate through the <scores> iterable, sorting out the stuffs as you go.

Answer 3

you could use reduce() function from functools module to get both lists at once check...

https://code.sololearn.com/cECfhVYWjJ2C/?ref=app

if you want to include 50 in result of second list (True == 1), then just change comparison operator to >= instead of > in 'fs' lambda used ('fs' stand for shortcut of 'filter_split') ;)

more about reduce():

https://docs.python.org/3/library/functools.html

https://thepythonguru.com/python-builtin-functions/reduce/

https://realpython.com/python-reduce-function/

https://www.geeksforgeeks.org/reduce-in-python/

Answer 4

Completa el código para iterar a través de la lista grades y mostrar solo los valores mayores a 50

for
grade
in
grades:

if
grade <= 50:

break >=50:
print(grade)