Python regex that will match anything that isn't a alphabet letter.

Answer 1

^a-zA-Z

Answer 2

your attempt?

Answer 3

Rellot's screwdriver

I wrote this

Import re

old_str = "da8v+i4d"
pattern = r'[0-9]'
new_str = re.sub(pattern, '', old_str)
print(new_str[::-1])

#that will match all numbers and replace them with an empty string, then Reverse the string right.
#but i also want it to match the special symbols

Answer 4

Bibek Oli is almost right, except he doesn't explicitly explain than its code should replace your 0-9 character range inside square brackets of your pattern ;)

the ^ (carret) at start of a character range is not negate it, so will match any character that are NOT listed after, rather than matching those wich are listed

however, you could make your regex replacement a few more efficient, by appending a + operator quantifier after the closing bracket: this will match one to any number of characters defined by the range, and so replace contiguous ones at once instead of replacing each one at a time ;P

pattern = '[^a-zA-Z]'

r before string is not required, as there's no ambiguous character in your regexp (antislashes), but may be put anyway (r doesn'r stand for regexp string but for raw string: doesn't use escape codes)

also, by using case insensitive modifier to your regexp, you could short a few the raw string ^^