Does anybody have any idea that why the output is not the sorted array and how should edit the code and why the output is trash

Question

#include <iostream>
using namespace std;
void swap(int *,int *);
void sort (int [],int );
int main()
{
const int size=12;
int a[size]={1,2,96,21,17,3,9,14};
sort(a,size);
for(int i=0;i<size;i++)
cout<<a[i]<<" ";}
void sort (int a[],int size)
{
int i,j;
int *p;
p=a;
for(i=0;i<size-1;i++)
for(j=1;j<size;j++)
if (*(p+j+1)<*(p+j))
swap ((p+j+1),(p+j));}
void swap(int *pa,int *pb)
{int t;
t=*pa;
*pa=*pb;
*pb=t;
}

Answer 1

Jayakrishna🇮🇳 Still it is not sorted

Answer 2

/* Corrected code :
Your size=12 is more than array size so counting garbage values.
In loop, 1st loop condition is should be I<size, next inner loop should be I<size-1 */

#include<iostream>
using namespace std;
void swap(int *,int *);
void sort(int [],int);
int main()
{

int a[]={1,2,96,21,17,3,9,14};
const int size=8;
sort(a,size);
for(int i=0;i<size;i++)
cout<<a[i]<<" ";
}
void sort (int a[],int size)
{
int i,j;
int *p;
p=a;
for(i=0;i<size;i++)
for(j=1;j<size-1;j++)
if (*(p+j+1)<*(p+j))
swap ((p+j+1),(p+j));
}
void swap(int *pa,int *pb)
{
int t;
t=*pa;
*pa=*pb;
*pb=t;
}

Answer 3

Guru patel I am getting correct order of sorting for this program. What order you getting wrong?