What is difference between 1 and 2 and why I am not getting the output in case 2??

Question

1.include <iostream>
#include<string>

using namespace std;
class my {
public:
void no(string x) {
name = x;
}
string getyes() {
return name;
}
private:
string name;

};

int main() {
my z;
z.no("No utput");
cout << z.getyes();
return 0;
}
2.#include <iostream>
#include<string>

using namespace std;
class my {
public:
void no(string x) {
x = name;
}
string getyes() {
return name;
}
private:
string name;

};

int main() {
my z;
z.no("No utput");
cout << z.getyes();
return 0;
}

Answer 1

In 2 nd one you are assigning value to a local variable , i .e . x

Answer 2

Shaik.Shahir do you realise what assigning a value means ? And how value is assigned to left side operand instead of right side one .

You never assigned value to name in 2nd case , how can you expect an output ?

Answer 3

Hooo!got it

Answer 4

But why I am not getting the output in case 2??