+ 5

Again. I can't find the bug 👇😔 pasword validation

cl = ['!', '@', '#', '

#x27;, '%', '&', '*'] num = ["1","2","3","4","5","6","7","8","9","0" ] ab = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] pw = input() m = 0 n = 0 abc = 0 for i in pw : if i in cl: m += 1 elif i in num : n += 1 elif i in ab : abc += 1 pr = True kr = True if abc >= 7 : pr = False kr = False if m < 2 : pr = True if n<2 : kr = True if pr or kr : print("Weak") if not pr and not kr : print("Strong")

python3

9th Jul 2021, 12:41 PM

UnTentetive

19 Respuestas

+ 8

Yes, that's what I'm trying to explain: By "characters" they don't mean number of of alphabetic characters. I think they mean total length of the string

9th Jul 2021, 1:24 PM

Lisa

+ 6

Is it the code coach task? I looked at the instruction text. Maybe min. 7 characters does not mean 7 alphabetic characters but rather a total length of 7?

9th Jul 2021, 12:56 PM

Lisa

+ 6

Great 👍

9th Jul 2021, 1:27 PM

Lisa

+ 5

Amit Ranjan Sahoo Here's a one-liner possibility: print(("Weak", "Strong")[len(k := input()) > 7 and sum(x.isdigit() for x in k) > 1 and sum(x in "!@#$%&*" for x in k) > 1]) # Hope this helps

10th Jul 2021, 4:28 AM

Calvin Thomas

+ 4

Can you please but your code in a playground script and then link it here?

9th Jul 2021, 12:46 PM

Lisa

+ 4

Lisa Ok, here it is 👇 https://code.sololearn.com/cQ2gkmtWBS2o/?ref=app

9th Jul 2021, 12:48 PM

UnTentetive

+ 4

Lisa Yes, i did that befor But now i tried all the charecter of my keyboard 👇👇

9th Jul 2021, 1:11 PM

UnTentetive

+ 2

Lisa Yes its cod coach task. Oooo, i listed alphabets🙁

9th Jul 2021, 12:59 PM

UnTentetive

+ 2

I just tried the task: It seems it is not required that the pw has 7 abc... It's enough if len(pw) >=7

9th Jul 2021, 1:09 PM

Lisa

+ 2

Lisa https://code.sololearn.com/c2RZVd2Edvht/?ref=app

9th Jul 2021, 1:13 PM

UnTentetive

+ 2

I would advise you to use regex for this problem.

9th Jul 2021, 3:29 PM

Pawel Zabinski

+ 1

What I meant is the following: pw = "12abc*** should be strong, too, because len(pw) >= 7 although it only has abc as alphabetic characters

9th Jul 2021, 1:18 PM

Lisa

+ 1

Lisa Hmm, i tried this ,but anathor bug obtained 👇👇 if len(pw) >14 And if len(pw) != 14 But it is not fully satisfy.

9th Jul 2021, 1:20 PM

UnTentetive

+ 1

Lisa In Pasword- 12abc*** the charecters are only 3(a,b,c)

9th Jul 2021, 1:22 PM

UnTentetive

+ 1

Lisa , Here "*" is a special charecter not only charecter.

9th Jul 2021, 1:23 PM

UnTentetive

+ 1

Lisa Yaaa, i tried and get succes 😀❤️. Thank you very much 😄

9th Jul 2021, 1:26 PM

UnTentetive

+ 1

Calvin Thomas Wow, you are pro-coder 😀👌🙏

10th Jul 2021, 4:34 AM

UnTentetive

+ 1

You are just counting alphabets that is greater than or equal to 7. It must satisfy all 3 conditions properly to say it as strong else it is evaluated as weak. Kindly make these changes 😀

10th Jul 2021, 1:37 PM

nithin.k.s