I have try to solve this question but i don't know what is wrong in my code. Only some case has passed. Tell my mistake not ans.

Question

You work in a sign factory, and the machine has started printing all of the signs backwards! The signs have already been packed into boxes of four signs each. Every letter on every sign is capitalized, so if the original sign was of a palindrome (a word or phrase that is the same backwards and forwards) you can still save those signs and not have to reprint them. Check each box to see if you should open it up to dig out the sign you can save, or if you need to just throw the whole box in the trash.

Task
Given the four words that were supposed to be contained in each box, determine if at least one of them is of a palindrome.

Input Format
Four strings that represent the word or phrase that was supposed to be printed on the signs inside each box.

Output Format
A string that say 'Open' if at least one of the boxes is a palindrome or 'Trash' if all of the signs are misprinted.

Sample Input
CAT
MONDAYS
RACECAR
TACOS

Sample Output
Open

Answer 1

pawan rathor 2.0

Problem is in taking input.

So As there are only 4 inputs then just do this

count = 0

for i in range(4):
word = input()

if word == word[::-1]:
count += 1

Answer 2

OMG!!! Nothing at all buddy. I am sure you will solve this problem.
I count on you.
Happy coding. Bye

Answer 3

I ᴀᴍ "Tɪᴍᴇ" thanks buddy 👍
Finally I have solved

Answer 4

1.there must be 4 inputs!!!
2.No need to uppercase them.

Answer 5

I ᴀᴍ "Tɪᴍᴇ" can you tell me what is wrong here

Answer 6

Change first 3 line of code to that:
box = [input() for i in range(4)]
count = 0
for i in box:

******
and change all word variable to box

Answer 7

Shadoff ok but not expecting output

Answer 8

Shadoff not understand

Answer 9

Do you know English?
what exactly from written above you didn't understand?

Put my code instead of your first three lines of YOUR code. (change word variable in YOUR code to box)

Answer 10

I know English but what do you mean
In your code

Answer 11

Shadoff thanks buddy I will try

Answer 12

This one work perfect , the code it's weird:
w1 = str(input())
w2 = str(input())
w3 = str(input())
w4 = str(input())
count= 0

if w1[0:]==w1[::-1]:
count+=1
elif w2[0:]==w2[::-1]:
count+=1
elif w3[0:]==w3[::-1]:
count+=1
elif w4[0:]==w4[::-1]:
count+=1

if count>0:
print("Open")
elif count==0:
print("Trash")

Answer 13

My code:count=0
word=input().upper().split()
for i in word:
if i[0:]==i[::-1]:
count+=1
if count>0:
print("Open")
elif count==0:
print("Trash")