Syntax Error fix ?

Question

Task :

Guessing a misspelled word into a corrected spelled word (in a list)

Words is a list of correct words

and terms are the misspelled words

class Dictionary:
def __init__(self, words):
self.words = words

def find_most_similar(self, term):
self.term = term
for i in range(len(self.words)):
if self.term[1:4] in self.words[i] and len(self.term) < len(self.words[i]):
return self.words[i]
elif self.term[1:4] in self.words[i+1] and len(self.term) < len(self.words[i+1]:
return self.words[i+1]

why is there a syntax error! please explain :<

Answer 1

Right off the bat, i can see in your final elif statement that you forgot closing parenthesis.

The exact error message would be very helpful

Answer 2

please post the actual error message or copy the code into the playgound, save and share here

Answer 3

class Dictionary:
def __init__(self, words):
self.words = words

def find_most_similar(self, term):
self.term = term
for i in range(len(self.words)):
if self.term[1:4] in self.words[i] and len(self.term) < len(self.words[i]):
return self.words[i]
elif self.term[1:4] in self.words[i+1] and len(self.term) < len(self.words[i+1]):
return self.words[i+1]

error = 'pineapple' should equal 'apple'

Answer 4

if its a syntax error, there will be an error message when you run the code. Copy and paste that please.

if it works, but just doesnt have expected output, than thats a logic error in your program.

Answer 5

Calvin Thomas i usually use pyperclip, doesnt seem to work on mobile though

Answer 6

Slick I see.

Answer 7

Ahmed Hassan

what a sh... isTHAT???

Answer 8

I fixed it but I still get on testcase wrong :<

Answer 9

Test case 3 = pineapple should equal apple

Terms = appl

Answer 10

Traceback (most recent call last):
File "tests.py", line 13, in <module>
test.assert_equals(test_dict.find_most_similar('coddwars'),'codewars')
File "/workspace/default/solution.py", line 11, in find_most_similar
elif self.term[1:4] in self.words[i+1] and len(self.term) < len(self.words[i+1]):
IndexError: list index out of range

Answer 11

Thanks! its an Index error it says, so whatever number was put into one of those index brackets [ ] is over the limit.

try printing that value. you may also be causght in the common, "off by one" problem.

Answer 12

wdym printing that value?

Like this? : print(len(self.words[i+1])

Answer 13

try printing i+1 in each loop, to see what the index value you plug in will be

Answer 14

class Dictionary:
def __init__(self,words):
self.words = words

def find_most_similar(self,term):
self.term = term
for i in range(len(self.words)+1):
if self.term[1:4] in self.words[i] and len(self.term) < len(self.words[i]):
return self.words[i]
elif self.term[1:4] in self.words[i+1] and len(self.term) < len(self.words[i+1]):
return self.words[i+1]

like this ?

Answer 15

its on line 13, if i+1 gives an index error, try it without the +1.

indexing starts at 0

Answer 16

like this

class Dictionary:
def __init__(self,words):
self.words = words

def find_most_similar(self,term):
self.term = term
for i in range(len(self.words+1)):
if self.term[1:4] in self.words[i] and len(self.term) < len(self.words[i]):
return self.words[i]
elif self.term[1:4] in self.words[i+1] and len(self.term) < len(self.words[i]):
return self.words[i+1]

Answer 17

yes, except it would aslo be in the return statement. try and take out the +1's

Answer 18

Traceback (most recent call last):
File "tests.py", line 5, in <module>
test.assert_equals(test_dict.find_most_similar('strawbery'),'strawberry')
File "/workspace/default/solution.py", line 8, in find_most_similar
for i in range(len(self.words+1)):
TypeError: can only concatenate list (not "int") to list

Answer 19

self.words+1 isn't a statement. I think you're trying to add a number and a list as the error says

Answer 20

Isnt that what u said? Though