I am trying to do operator overloading in Queue But there is some error in the code. This is project problem of C++ Queue Manage

Question

#include <iostream>
using namespace std;

class Queue {
int size;
int* queue;

public:
Queue() {
size = 0;
queue = new int[100];
}
void add(int data) {
queue[size] = data;
size++;
}
void remove() {
if (size == 0) {
cout << "Queue is empty"<<endl;
return;
}
else {
for (int i = 0; i < size - 1; i++) {
queue[i] = queue[i + 1];
}
size--;
}
}
void print() {
if (size == 0) {
cout << "Queue is empty"<<endl;
return;
}
for (int i = 0; i < size; i++) {
cout<<queue[i]<<" <- ";
}
cout << endl;
}
//your code goes here
Queue operator+(Queue q2){
Queue q3;
int size=0;
for(int i=0;i<4;i++){
q3.queue[size]=this->queue[size]+q2.queue[size];
size++;
}
return q3;
}
};

int main() {
Queue q1;
q1.add(42); q1.add(2); q1.add(8); q1.add(1);
q1.print();
Queue q2;
q2.add(3); q2.add(66); q2.add(128); q2.add(5);
q2.print();
Queue q3 = q1+q2;
q3.print();
return 0;
}

Answer 1

Instead of creating a new varible size , use q3 object size member variable.

Queue operator+(Queue q2){
Queue q3;

for(int i=0;i<4;i++){
cout<<q2.queue[q3.size]<<endl;
q3.queue[q3.size]=this->queue[q3.size]+q2.queue[q3.size];
q3.size++;
}
return q3;
}

Answer 2

Thanku so much Im trying to sort out this problem from last two hours .

But i think so there is no need to print this statement :
cout<<q2.queue[q3.size]<<endl;

Answer 3

Rgodella ofcourse you don't need to , i was using it to test it and forgot to delete it!