Help me to fix the error??

Question

a = {'a':'z','b':'y','c':'x','d':'w','e':'v','f':'u','g':'t','h':'s','i':'r','j':'q','k':'p','l':'o','m':'n','n':'m','o':'l','p':'k','q':'j','r':'i','s':'h','t':'g','u':'f','v':'e','w':'d','x':'c','y':'b','z':'a'}
b = input()
for key , value in a.items():
b = b.replace(key,value)
print(b)
Here's the question:
You are trying to send a secret message, and you've decided to encode it by replacing every letter in your message with its corresponding letter in a backwards version of the alphabet.
What do your messages look like?

Task:
Create a program that replaces each letter in a message with its corresponding letter in a backwards version of the English alphabet.

Input Format:
A string of your message in its normal form.

Output Format:
A string of your message once you have encoded it (all lower case).

Sample Input:
Hello World

Sample Output:
svool dliow

Answer 1

Shaik.Shahir ,

before we can help you, you should show us your attempt first. if you have not done a try by yourself upto now, please do so. Put your code in playground and link it here.

thanks!

Answer 2

a = {'a':'z','b':'y','c':'x','d':'w','e':'v','f':'u','g':'t','h':'s','i':'r','j':'q','k':'p','l':'o','m':'n','n':'m','o':'l','p':'k','q':'j','r':'i','s':'h','t':'g','u':'f','v':'e','w':'d','x':'c','y':'b','z':'a'}
b = input()
for key , value in a.items():
b = b.replace(key,value)
print(b)

What is missing in this code??

Answer 3

This task has one subject:
To find the corresponding character in an reversed alphabet and replace it.

For me, you can create two main variables, one that contains the regular alphabet, and one another that contains the reversed alphabet.

Then, iterating over each character of the current word, find its index and return the same index but at the reversed alphabet.

And that's it !
Just be a little smart and share your try here from the code playground 😁👋

Answer 4

No it's not working

Answer 5

This explains the .get() method :

https://www.w3schools.com/JUMP_LINK__&&__python__&&__JUMP_LINK/ref_dictionary_get.asp

Answer 6

Shaik.Shahir I'm really sorry for giving you the incorrect code. I've updated mine, so you may check that out. Here's a working version of your code:

a = {'a':'z','b':'y','c':'x','d':'w','e':'v','f':'u','g':'t','h':'s','i':'r','j':'q','k':'p','l':'o','m':'n','n':'m','o':'l','p':'k','q':'j','r':'i','s':'h','t':'g','u':'f','v':'e','w':'d','x':'c','y':'b','z':'a'}

for x in input().lower():
print(a.get(x, x), end="")

# Hope this helps

Answer 7

Would please explain me the using of "get" function?

Answer 8

low = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v",
"w", "x", "y", "z"]
upp = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V',
'W', 'X', 'Y', 'Z']

prompt = input()

for c in prompt:
if c.islower():
count = low.index(c)
if count == 0:
rev = count -1
elif count > 0:
rev = (count * (-1)-1)
print(low[rev])
if c.isupper():
count = upp.index(c)
if count == 0:
rev = count -1
elif count > 0:
rev = (count * (-1)-1)
print(upp[rev])

Answer 9

I feel like the instructions are fairly clear. It wants you to take an input string, say "dog", and encode it by taking the alphabet, and reversing its order (ie, instead of 'abcd...' it's 'zyxw...'). So for "dog", we'd have "wlt".

so here's the input/output format:

input: dog

output: wlt

From here on it's up to you to figure out.

Answer 10

Shaik.Shahir I guess that the input needs to be in the lower form. Try changing the first line to b.input().lower().

Answer 11

Shaik.Shahir The get() method of the dict class returns the corresponding value if the first argument (the key) is found. Else, it returns the second argument.

Answer 12

I don't understand the output format in the question
So please explain it!

Answer 13

Abcdefghijklmnopqrstuvwxyz becomes
Zyxwvutsrqponmlkjihgfedcba
First position in first string becomes first position in second string. And so on.

Answer 14

Shaik.Shahir You may try using the ord() function to make the job easier.

Answer 15

Shaik.Shahir Here's a possible solution:

https://code.sololearn.com/cP4X13LiMhqT/?ref=app

# Hope this helps

Answer 16

list = {
'a': 'z','b': 'y',
'c': 'x','d': 'w',
'e': 'v','f': 'u',
'g': 't','h': 's',
'i': 'r','j': 'q',
'k': 'p','l': 'o',
'm': 'n','n': 'm',
'o': 'l','p': 'k',
'q': 'j','r': 'i',
's': 'h','t': 'g',
'u': 'f','v': 'e',
'w': 'd','x': 'c',
'y': 'b','z': 'a'
}
string = str(input())
a = ''
for char in string.lower():
if char == " ":
a += char
else:
a += list[char]

string = a
print(string)