Deja Vu Challenge

Question

Hi i Need help With my Code. 4 out of 5 cases are Succesful, only the Last case fails… i dont get the mistake to be honest 🙈

#include <iostream>
using namespace std;

int main() {

bool DejaVu = false;
string random, buffer;
cin>>random;

for(int i = 0; i<=random.size(); i++)
{
if(buffer.find(random[i]) == string::npos)
{
buffer += random[i];
}
else
{
cout<<"Deja Vu";
DejaVu = true;
}
}

if(DejaVu == false)
{
cout<<"Unique";
}

return 0;
}

Answer 1

For a character in a string repeating more than 1 time it outputs that many "Deja Vu".So , breaking the for loop after first repeating character is found , should do the work.

Answer 2

That was the error 🙄 Thank You so much 🎉🎉 I hadnt this possibility in mind at all 🙈