I want to create a python code which gives me the sum, avg of odd numbers between the two numbers the user entered. (While loop)

Question

I want to create it with while loop and also display the odd numbers between those two numbers entered by user along with there sum and average

The code i wrote just displays the list of odd numbers between those two digits.

mini=int(input("Enter the minimum number:- "))
maxi=int(input("Enter the maximum number:- "))
while(mini<maxi+1):
if(mini%2!=0):
print(mini, end=' ')
mini+=1

Can anyone please add the ability to get and display the sum and average of all the odd numbers between those two entered? Without using function

Answer 1

The problem is, you have not assigned sum before using it (you typed s instrad of sum above)

Print the total sum and the average only after the loop.

https://code.sololearn.com/cyIzQA0kI122/?ref=app

Answer 2

Make an empty list before you enter the loop. Whenever a muber is odd, append it to this list.
Then, after the loop, calculate sum and average with this list.

Answer 3

Lisa so I cant use list right now....

Answer 4

I think you can do this as a beginner!

# create an empty list before entering the loop
odd_nums = []

# when mini is odd (inside the loop), append it to this list
odd_nums.append(mini)

Then you have all numbers for your calculations in odd_nums!

Answer 5

Well, I sketched a list-based approach for you, so now you know.

If you are a beginner, I recommend starting the Python for Beginners course: lists are covered there :)

Answer 6

you could assign

sum = 0
n = 0

before entering the loop. When you find an odd number, you add it to sum and increase n by one.
At the end of the loop you have the sum and get the average as sum/n

Answer 7

Lisa thank you so muchh i got it now

Answer 8

minimum = 10
print("min",minimum )
maximum = 15
sum = 0
print("top sum",sum)
count = 0
while minimum < maximum + 1:
if minimum % 2 == 0:
sum = minimum + sum
print("sum inside",sum)

minimum += 1
count +=1

print("sum outside",sum/count)

Answer 9

Lisa Acctually i am just a beginner, so if you could do that for me i would learn from it and keep it in my mind the next time for sure.

Answer 10

Lisa acctually i am just knowing (if, else, elif, while)

Answer 11

Lisa i have just started python 3 days ago and what i want to add in this code can be done by while and all but i am unable to thats why i thought to get help from solo learn and keep it in my.mind from the next time onwards

Answer 12

Lisa is there any other way than append?

Answer 13

Lisa basic way which i can do?

Answer 14

Lisa thanks a lot for helping, but trust me its sounding really complex in my head. I know i sound like a noob but can u add this approach to my code so that then i will dry run it and analyse what u wanted me to do?

Answer 15

# in loop
if mini%2 != 0:
sum = sum + mini
n = n + 1

# in the end
print(sum)
print(sum/n)

Answer 16

Lisa mini=int(input("Enter the minimum number:- "))
maxi=int(input("Enter the maximum number:- "))
s=0
n=0
while(mini<maxi+1):
if(mini%2!=0):
sum=s+mini
n=n+1
print(mini, end=' ')
print(sum)
print(sum/n)
mini+=1

Its acctually not working as desired, i am sure its my mistake though....

Answer 17

Lisa by the way whenever you have time can you tell me what exactly did you do to make my code the work i was aiming onto. Like i wanna understand the logic of taking s=0 and everything u added in my code. (Thanks a lot for helping so much)

Answer 18

harmeet singh I added comments in my code example

Answer 19

sum should be called outside while loop function

Answer 20

harmeet singh How about this? :-

min = int(input())
max = int(input())
sum = len = 0
while min <= max:
if min & 1:
print(min)
sum += min
len += 1
min += 1
print(sum)
print(sum / len)

# Hope this helps