Can't differentiate ++b, b and b++

Question

When I wrote the program with the input a as 5 b as 3 and c as 2
{
int a,b,c,d;
cout <<"a=";
cin>>a;
cout<<"b=";
cin>>b;
if(b++<a){
cout<<"c=";
cin>>c;
cout<<"your ans:"<<a+b*c<<endl;
}
d= a%b;
cout<<"d="<<d<<endl;

return 0;
}
It kept giving me the answer for "your ans:" as 13 instead of 11 and the answer for d as 1 instead of two even though I didn't declare b=b++ or ++b, why?

Answer 1

Read about "pre-increment" and "post-increment"

Answer 2

The pre increment (--a) and post increment (a++) operators will actually make more sense when used in expressions.
Both operators increment a variable by one but the difference is about the order of events in which they happen. ie what comes first.
For example
a = 0
b = ++a
print(a, b) // 1 1
Before b is assigned the 'a' variable is first incremented by one and then b is assigned the new value of a.

a = 0
b = a++
print(a, b) // 0 1
So you see the difference, the later assigned b to the value of a and then a was incremented by one.
I hope this helps you to differentiate the two operators.