How the output is 3 ??

Question

#include <stdio.h>
#define square(x) (x * x)

int main()
{
int x, y = 1;
x = square(y + 1);
printf("%d\n", x);
return 0;
}

Answer 1

square(y+1) replaces x so it becomes (y+1*y+1) =3

Answer 2

Abhay ok 😮 so it will send the argument without adding them..