Can I condense this?

Question

Given two sentences, you need to find and output the number of the common words (words that are present in both sentences).

Sample Input:
this is some text
I would like this tea and some cookies

Sample Output:
2

The words 'some' and 'this' appear in both sentences.
You can use the split() function to get a list of words in a string and then use the set() function to convert it into a set. For example, to convert the list x to a set you can use: set(x)

##MY CODE
s1 = input()
s2 = input()

split1 = s1.split(" ")
split2 = s2.split(" ")

set1 = set(split1)
set2 = set(split2)

print (len(set1&set2))
##

0ut of curiosity, are there other ways to do this?

Answer 1

setW = set(s1.split() + s2.split())
print (len(setW))

:)

Answer 2

Candace Taylor
I enjoyed the answer from SoloProg so much that I had to offer another version:

print(len(set(input().split(" ")) & set(input().split(" "))))

Answer 3

SoloProg Candace Taylor Rik Wittkopp Since a space is the default separator for the split method, you never need to write split(" "). It's simpler just to write split() which gives the same result. 🙂

Answer 4

s1 = input()
s2 = input()
print(len(set(s1.split()) & set(s2.split())))

Answer 5

David Ashton Thanks!
I always thought split() would create a list containing each letter.

I will play & learn

EDIT -> As I was playing, I realised that I knew this but had forgotten. 🤣😂

Which highlights the importance of continuous practice

Answer 6

We could write everything in a single (if that is what you want)

Answer 7

Candace Taylor ,

here are 2 samples doing it with other approaches:

# the basic way:
s1 = "lena tim lisa sandra tom john amy"
s2 = "bob mel tim barb lisa simon lena"

total = 0
for name in s1.split():
if name in s2:
total +=1
print(total)

# or doing it with a list comprehension:
print(sum([1 for name in s1.split() if name in s2]))

Answer 8

Candace Taylor, SoloProg , I agree with David Ashton :
https://code.sololearn.com/c4jj180j31kX/?ref=app

Answer 9

Just wanted to see some other approaches/code that would do the same thing

Answer 10

Candace Taylor
Thanks for best answer Candace, but please return it to Soloprog as I just piggybacked off his concept.
😁👍

Answer 11

Didnt realize I did that but thanks to you both! I love seeing different ways to write the same code, it really helps me understand whats going on!

Answer 12

s1 = "lena tim lisa sandra tom john amy"
s2 = "bob mel tim barb lisa simon lena"

setW = set(s1.split() + s2.split())
print(len(set(input().split(" ")) & set(input().split(" "))))

Answer 13

print(len(set(input())&set(input())))

Answer 14

s1 = input()
s2 = input()
x1 = s1.split()
x2 = s2.split()
d = set(x1) & set(x2)
print(len(d))

Answer 15

s1 = input()
s2 = input()
splits1 = s1.split()
splist2 = s2.split()
sets1 = set(splits1)
sets2 = set(splist2)
commonset = (sets1 & sets2)

print(len(commonset))

Answer 16

s1 = input()
s2 = input()
s1.split()
s2.split()
i=0
L1= set(s1.split() )
L2 = set(s2.split() )
for w in L1:
for w1 in L2:
if w==w1:
i+=1
print(i)

Answer 17

s1 = input()
s2 = input()

split1 = s1.split(" ")
split2 = s2.split(" ")

set1 = set(split1)
set2 = set(split2)

print (len(set1&set2))