Me again. Still doesn't really work.

Question

Do While Loops

Write a program that takes N numbers as input and outputs the numbers from N to 0, skipping the ones that are multiple of 3.

Sample Input
7

Sample Output
7
5
4
2
1
0

My code:

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt(); // N

while(number > 0) {
if(number%3==0)
{
continue;
}

System.out.println(number);

number = number - 1;

}
System.out.println("0");

}
}

What is still wrong ? My output is : Execution Timed Out!

Answer 1

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt(); // N

while(number>0) {
if (number%3==0){
number = number - 1;
continue;
}
System.out.println(number);
number = number - 1;
}

System.out.println("0");
read.close();

}
}

Answer 2

//it goes infinite after number%3 condition because you need to decrement it

Answer 3

Thank you so much, Edwin. You helped me a lot.

Answer 4

Lisa Kraack
you're welcome.

Answer 5

Please remember to put your code in a playground script and link it here – that way it is easier to read and easier to test if necessary! :)