The given program defines a function printBill(), which takes one string argument and outputs formatted text. You need to take

Question

My code
Def printBill(text)
Print("=====")
Print(text)
Print("=====")

PrintBill(text=int(input()))
It's just work for 1 chase, please help me find the error

Answer 1

Mabey cause it says it takes a string and you supply it with an int. It gives you an example in the problem itself

Answer 2

Try this one:
-Add a colon after you define your function
-The last line don't overthink because the user can enter either an integer or a string so change it with printBill(input())
Your final code should look like this

def printBill(text):
print("======")
print(text)
print("======")
printBill(input())

Answer 3

Your question got cut off.

Answer 4

Syekh Guntur Amara Putra ,

if you really have a problem, you should put a bit more effort. we need some more details from you:

▪︎give a clear and complete description about your task
▪︎if your question is related to an exercise in a tutorial, please mention the tutorial name and the lesson number
▪︎if there are error messages please post them here
▪︎give at least one sample with input data and the expected output
▪︎to be able to find out the issues you have, we need to see your code
    => please put your code in playground, save it there and post a link to it here.

thanks for your understanding!

Answer 5

Why so many wrong answer please correct it and bro improve your syntax there are some many errors.

def printBill(text):
print("======")
print(text)
print("======")

printBill(text=input())

and get your nice output.
Just chill

Answer 6

Well took almost a day to solve this , but this is how it’s done-

def printBill(text):
text = str(text)
print(“=====“)
print(text)
print(“=====“)
text=input()
printBill(test)

Answer 7

def printBill(text):
print("======")
print(text)
print("======")
printBill(input())

done...!

Answer 8

def printBill(text):
print("======")
print(text)
print("======")
printBill(input())

Answer 9

Both are correct

Answer 10

Slick
The given program defines a function printBill(), which takes one string argument and outputs formatted text.
You need to take the user input and call the function by passing the input as its argument.
That the question

Answer 11

♤♢☞ 𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 ☜♢♤
I don't know what's wrong with my code

Answer 12

We don't know what's wrong either, please provide an example input and output.

Answer 13

Slick it's hidden chase, I can't see.
I stuck in basic pyhton on argument point 38.2 can u help me sir?

Answer 14

We can help, but we need more info. Test cases do not matter. If you understand the problem, then please give us some input and output examples so we can understand what's wrong in your code.

Answer 15

The given program defines a function printBill(), which takes one string argument and outputs formatted text.
You need to take the user input and call the function by passing the input as its argument.
You need to only call the function, as it will take care of the output.

That the question

And this my code
def printBill(text):
print("======")
print(text)
print("======")

printBill(text=int(input()))

This the results for chase 1
Input 428977

Your output
=====
428977
=====

Expected output
=====
428977
=====

It's just work for chase 1, but not for another chase, there are 3 chase

Answer 16

Slick Lothar I don't know what's wrong with my code

Answer 17

Slick ♤♢☞ 𝐊𝐢𝐢𝐛𝐨 𝐆𝐡𝐚𝐲𝐚𝐥 ☜♢♤ thx u for helping me

Answer 18

Because thats not how
Parameters work in Python,
Do like:
def printBill(text):
print("======")
print(text)
print("======")
printBill("something")

Answer 19

def printbill(text):
print("===")
print(text)
print("===")
s=input()
printbill(s)

Answer 20

This is the correct answer:

def printBill(text):
print("======")
print(text)
print("======")
printBill(input())