+ 1
How can I search any word in any text and print a message that says word was found or not? Python
That's what i've done but this programme just can find 2 words in text def search (anytext, anyword): for i in anytext: if i == " ": index = list(anytext).index[" "] word1= list(anytext)[index:] word2= list(anytext)[(index + 1):] if word1 == list(word): print ("Word found") elif word2 == list(word): print ("Word found") else: print ("Word not found") text = input() word = input() print(search(text, word))
9 Respuestas
+ 5
this is the complete task description:
You’re working on a search engine. Watch your back Google!
The given code takes a text and a word as input and passes them to a function called search().
The search() function should return "Word found" if the word is present in the text, or "Word not found", if it’s not.
Sample Input
"This is awesome"
"awesome"
Sample Output
Word found
▪︎so you can cut down your code to:
def search(text_, word_):
if word_ in text_:
return "..."
else:
return"..."
text = input()
word = input()
print(search(text, word))
+ 4
Pranto ,
there is a real bunch of issues in your code, that could easily be found by running / testing the code.
list(x) creates this list: ['h', 'o', 'l', 'a', ' ', 'a', 'b', 'c', ' '], so the word can not be found in the string. you can use:
if "abc" in X:
...
your code with some comments:
X = “hola abc “ # 2 x wrong quotes, has to be " "
if “abc” in list(x): # wrong spelling ox 'x', is declared as "X" || list(x) creates this: ['h', 'o', 'l', 'a', ' ', 'a', 'b', 'c', ' ']
print(“found”) # 2 x wrong quotes
else:
pass
#..............
#You can use (in) to search a value.
+ 3
Матвей Стаселько ,
are you talking about the python tutorial for beginner, lesson number 45 (search engine)?
+ 1
You could just check
if word in text:
# do something
If you want to check several words, you can do something like
for word in words:
if word in text:
# do something
(words would be a list of words)
+ 1
Lorhar, yes!
+ 1
Yes, but i still can't do it :)
+ 1
Oh, thanks!
I thought it would be harder but it is really simple
+ 1
Lothar thanks man i made a mistake. I am correcting.
0
x = “hola abc “
if “abc” in list(x):
print(“found”)
else:
..............
You can use (in) to search a value.