What’s wrong with my code?

Question

You’re making a calculator that should add multiple numbers taken from input and output the result.

The number of inputs is variable and should stop when the user enters "stop".

Sample Input
4
32
6
stop

Sample Output
42

Use an infinite loop to take user input and break it if the input equals "stop".

sum=0
n=1
while True:
x=input()
if int(x)>0:
x += sum
else:
break
n+=1

print (sum)

I’m getting a “cannot concatenate str and int” error.

Answer 1

change line 4:

x=input()

# to

x = int(input())

input() returns a string, so even if you enter 5. It will register that as the string "5". And you can't add a number and a string.

Answer 2

Steele Jackson ,

this is your code re-arranged and slightly modified:

total=0 # variable is for running total / sum, but should not be named 'sum' as this is builtin function
while True:
x=input() # input has to be taken in string, not in integer, as we have to handle the 'stop' input << Slick
if x == "stop": # first we check for 'stop'
break # in this case we leave the loop
else:
total += int(x) # running total will be handled

print (total) # finally we print the total

Answer 3

sum is int (integer, means number)
input() is str (string, means some text)

convert string to number with int() method.

x = int(x)

Apart from syntax error, there is a logic error.

Instead of incrementing input by sum, you should increment the sum by input.

sum += int(x)

Answer 4

Steele Jackson ,

on the left side of an assignment we can not have any functionality. it just gets assigned the result of the expression being on the right side

total += int(x) is identical with: total = total + int(x)

Answer 5

Lothar thank you for the individual line explanations. One more thing - why does total += int(x) work, and int(x) += total not work? Wouldn’t the program be adding int(x) to the running total, and not the other way around?