Computing a fare meter using java (What is wrong with my codes?)

Question

import java.util.Scanner;

class Main{
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
System.out.print("Enter the distance travelled (meters): ");
int dist = in.nextInt();

double fare = 2.50;
if (dist <= 250)
fare = 40;
else if (dist <= 450)
fare = 40 + 2.50;
else if (dist <= 451)
fare = 40 + 5;
else if (dist <= 700)
fare = 40 + 7.50;
else if (dist <= 701)
fare = 40 + 10;
else if (dist <= 900)
fare = 40 + 12.50;
else if (dist <= 901)
fare = 40 + 15;
else

fare = 40 + 15 + 2.50 ;
System.out.println("Total cost = P"+fare+0);

}
}

Answer 1

Martin Taylor thank you for your feedback! I’ll try to edit my code and make it better. Have a nice day!

Answer 2

Atul [Inactive] this is a program that answers the following problem situation:

The taxi has a base fee of 40.00 for the first 250 meters. An additional 2.50 is added for every succeeding 200 meters. Compute and print the total fare that you is needed to pay.

Answer 3

Nothing is wrong with your code please tell the expected output?

Answer 4

The expected output is

Enter the distance travelled (meters):

Total cost =

Answer 5

dist=input("Enter the distance travelled (meters): ")
print()

base_fare=40.00
charge_per_meter=2.50
free_distance = 250
fare=0
succeeding_dist = 200

if (float)(dist) <= free_distance :
fare = (float)(base_fare)

else :
calculate = (( ((float)(dist) - (float)(free_distance)) / succeeding_dist) * (float)(charge_per_meter));
fare = (float)(base_fare) + (float)(calculate)

print("Total cost = P%0.2f" %(float)(fare))

'''
The taxi has a base fee of P40.00 for the first 250 meters.
An additional P2.50 is added for every succeeding 200 meters.

'''

Answer 6

is there a C Language version of this code, because we have the same exact question.