Can someone please help me explain this code.

Question

x = 5
def fun(x):
x = x - (x-2)
return x
print(fun(fun(fun(x-1))))

Three questions:

Is this a form of recursion?

On line 5. Does the amount of ‘(fun)’ make any difference? Because no matter how many ‘fun’ I put I get the same output which is 2

Does the code end after going through function the 1st time or does it end after the 3rd time (because there are 3 fun’s)?

Answer 1

x-(x-2) = 2
Therefore fun() will always return the value 2.
The function is called three times. The first time with 4 (x-1), the other times with 2.