Extract First name, Middle name and last name

Question

Problem Statement:

You need to process an input string, accepted from standard input. These are basically names which are to be separated in First Name, Middle Name and Last Name. In the platform you need to process a single string from standard. But you can extend the code later in your system so that you read data from an excel file (consisting of names) and produce a csv file as output.

Input: You need to read a line from STDIN to extract First Name, Middle Name and Last Name

Output: First Name, Middle Name and Last Name (separated by a single comma)

Test Cases:

Input: Krunalkumar Haribhai Ramanujsadhu
Output: Krunalkumar,Haribhai, Ramanujsadhu

Input:Mukul Gupta
Output:Mukul,,Gupta

Input:Manoj Kumar Singh Gowda
Output:Manoj,Kumar,Singh,Gowda

My attempt with python

https://code.sololearn.com/c1eKydNDawy7/?ref=app

Answer 1

https://code.sololearn.com/c3u7K9XXLQoe/?ref=app
https://code.sololearn.com/c32exzR2P122/?ref=app

Answer 2

Màñøj Check this code u will get that u want....
https://code.sololearn.com/c32exzR2P122/?ref=app

Answer 3

Màñøj ok I will fix it soon

Answer 4

variables must never start with numbers.

your function expects 3 parameters and you only passed one.

you are separating(split) using an empty string, this will separate

Python is sensitive to indentation

Answer 5

Rules for creating variables in Python:

A variable name must start with a letter or the underscore character.

(Your fault ) A variable name cannot start with a number.

A variable name can only contain alpha-numeric characters and underscores (A-z, 0-9, and _ ).

Answer 6

There are some issues in your code:
1.variable names can't start with a number.
2.split() seperates words with spaces, lines, and so on, but split("") does nothing.
3. Thete is an extra space before the print function.
4. The function needs 3 variables, but you give it a list.

Look at this:

https://code.sololearn.com/c4046t6IgkIO/?ref=app

Answer 7

Màñøj
def sep_names (name):
return ("{}, {}, {}". format (name[0], name[1], name[2]))
print (sep_names (input().split(' ')))

or

def sep_names (fname, mname, lame):
return ("{}, {}, {}".format(fname, mname, lame))
print (sep_names(*input().split(' ')))

Answer 8

✌️cool

Answer 9

Màñøj
Here's a way for you to look at;

first, *middle, last = input().split()

print(f"{first}, {middle[0] if middle else ''}, {last}")

Using the packing operator * for the second variable name will place any remaining values (names) into a list by the name 'middle'. Then you can just output the 0th value if the list isn't None. The first and last names will always need to be supplied and their values will be applied to the corresponding names.

Answer 10

Yeah ur correct, thanks u for help to understand

Answer 11

What if we give 2 values instead of 3 values

Answer 12

Màñøj I changed the code. Take a look.

Answer 13

Nice work👍

Answer 14

Màñøj

txt=input().split()
if len(txt)!=3:
print('invalid input, enter more than 3 word')
else:
sep=','
print(sep.join(txt))

Answer 15

Màñøj
Well, it's easy. ( if) can be changed. important using if join method.

Answer 16

Try this 😊 :

type=["First","Middle","Last"]
for i,name in enumerate(input().split()):
print(type[i]+" name is '"+name+"'")

https://code.sololearn.com/crUNEMX185xX/?ref=app

Answer 17

print(','.join(input().split()))

Answer 18

This is your python coding :-💯

def sep_names (fname, mname, lame):
return ("{}, {}, {}".format(fname, mname, lame))
print (sep_names(*input().split(' ')))

Answer 19

Hemmat
Works only if we enter more than 3 values..
But it should work for all values

Answer 20

Look at the testcases SAN