Java program for fibonacci series

Question

import java.util.Scanner;
public class Program {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
int a = 0;
int b = 1;
int i=1;
System.out.println(a);
System.out.println(b);
if(i<x){
int sum = a+b;
System.out.println(sum);
a=b;
b=sum;
i++;
}
}
}

I m not getting required output while using if loop.
But when I used for loop I got it. Can anyone tell me what's wrong in this if loop

Answer 1

for loops continue to run through the set parameters, acting upon the statement each iteration.

An if statement is assessed once
if (i < x) -> true
sum = a + b -> 0+1 -> 1

Answer 2

You have created three variables a b and i. After that u printing values of a and b . But your if condition will work only once here u need to use loop . Else your code will give sum of numbers only once and also add else clause if your condition gonna be false you can give any message

Answer 3

Shira thank u

Answer 4

Yehhh Rik Wittkopp
Thank u

Answer 5

Sonali Kala int a=21 and b=8 here two variables are declared which types are int after in print statement there was written (a/++b)%3 here it will solve according to precedence so first bracket will be solve (a/++b) remember if u have pre increment or pre decrement then it will solve in the whole expression then this increase value will be use her b is incremented by 1 so now b become 9 and (a/++b)= 21/9=2 then modulo %3 ---> = 2%3 here your numerator is smaller than denominator that why the result will be 2 if numerator is greater then your remainder will be the output 3%2 =1

Answer 6

Shira ohhh when the numerator is greater we get output it as it is.
that means 4%5 ...o/p.. 4
And for 5%4 ... O/p .. 1

Answer 7

Sonali Kala yep

Answer 8

I too am learning java
take a look at my approach

https://code.sololearn.com/clkdEHv0nl7S/?ref=app

Answer 9

"if" is not a loop
it executes only one time

"while" and "for" are loops.
It iterates through the code block till a certain condition is not satisfied.
If no terminating conditions are described, the loop runs infinitely.

Answer 10

Harsha S thanks

Answer 11

Shira no problem...
Can u explain me the last ques.. (java challenge)

Answer 12

Shira thank you