how to round division of any number without math round() fx in c and c++?

Question

for ex ((2*100)/3) should be 66.67 so its rounded value must be 67

Answer 1

Try using ceil() with required header files.
https://code.sololearn.com/cWf030i39pru/?ref=app

Answer 2

You can do something like this 👇

d = m/n;
r = m%n;
if (r >= n/2)
roundedVal = d+1 ;
else
roundedVal = d ;

Answer 3

//For C

https://stackoverflow.com/questions/2422712/rounding-integer-division-instead-of-truncating

https://stackoverflow.com/questions/42885659/round-off-float-value-in-c-without-in-built-functions

//For C++

https://stackoverflow.com/questions/44848113/rounding-off-floating-point-value-in-c-without-using-build-in-functions

Answer 4

Harshit Mishra Here's something you could do:

float num = 66.67;
int floored = (int) num;

int result = floored+(num-floored>=0.5);

(Not sure if this is the right way to do it as it's been a long time since I've brushed up on my C skills)