Can you un-decorate a function?

Question

If there is a decorator function: decorator(func) and a function: func1(), and you apply the decorator on func1 by @decorator before the definition, can you still access the original "un-decorated" function somehow?

Answer 1

There appears to be a partial 'yes' answer to this question.

The update_wrapper function from functools adds a .__wrapped__ attribute which, since Python 3.4 always refers to the wrapped function. Functools further provides a convenience function for update_wrapper, the wraps function.

With that you can wrap your functions with custom wrappers and access the unwrapped via .__wrapped__. I have tried the following here in the playground and it works:

from functools import wraps

def log(f):
@wraps(f)
def logger():
print("[**LOG**] ", f())
return logger

@log
def func():
return "This message"

print(dir(func))
print(func.__wrapped__())

The first print shows the existence of the .__wrapped__ attribute. The second print prints "This message".