This is the mysql question, help me to write the query

Question

Query the two cities in STATION with the shortest and longest CITY names, as well as their respective lengths (i.e.: number of characters in the name). If there is more than one smallest or largest city, choose the one that comes first when ordered alphabetically.
The STATION table is described as follows:
STATION
Field Type
ID. NUMBER
CITY. VARCHAR2(21)
STATE. VARCHAR2(2)
LAT_N. NUMBER
LONG_W. NUMBER
where LAT_N is the northern latitude and LONG_W is the western longitude.
Sample Input:
For example, CITY has four entries: DEF, ABC, PQRS and WXY.
Sample Output:
ABC 3
PQRS 4
Explanation:
When ordered alphabetically, the CITY names are listed as ABC, DEF, PQRS, and WXY, with lengths 3,3,4, and 3. The longest name is PQRS, but there are 3 options for shortest named city. Choose ABC, because it comes first alphabetically.
Note:
You can write two separate queries to get the desired output. It need not be a single query.

Answer 1

For shortest city name :

SELECT city
FROM station
ORDER BY LENGTH(city), city
LIMIT 1;

Using order by clause to order city name in ascending order based on length of name and it's alphabetical order. LIMIT 1 to select only first record.

You can find longest city name by changing order from ascending to descending.

SELECT city
FROM station
ORDER BY LENGTH(city) DESC, city
LIMIT 1;