Kinda need some help here

Question

#include <iostream>
using namespace std;

int num[6];
char op;

int main(){
for(int i=0;i<6;i++){
cin >> num[i];
cin >> op;
}
for(int i=0;i<6;i++){
switch(op){
case '+':
num[i+1]=num[i]+num[i+1];
break;
case '-':
num[i+1]=num[i]-num[i+1];
break;
default:
cout << num[i];
return 0;
break;
}
}
cout << num[5];
return 0;
}

//examples: 1+2+3+4+5+6

//examples: 5-6-7-7-8-9

Can someone help me how to make it calculate addition and subtraction together like: 1+2-6+5-7...etc (same with multiplication and division)

Answer 1

Apparently we can do this without using any array.

https://code.sololearn.com/cS7506j5QXtF/?ref=app

Answer 2

Vicent Roxan revamp the input loop. Consider these problems:

- After every input number it tries to read an operator, whereas after the last number it does not have one. Try looping only 5 times, instead of 6, then add one more input that reads the final number.

- op would hold only the last operator. Each iteration replaces the previous value. Maybe op should be an array, too.

Answer 3

I have an idea with '+' and '-'. But the idea of multiplication and division (from the comment), isn't all too easy cause there are operator precedence to consider.