How to print a certain index differently.

Question

If you know Python's Colorama module, you know you can print out a string in whatever color you like right.
Example:

import colorama
print(colorama.Fore.RED + "This is gonna be printed out in red")
print(colorama.Fore.GREEN + "This is gonna be printed out in green")

Now back to my question, how do i loop through a list but do something (change the color) when the index is equal to i.
i mean something like:
for i in mylist:
print(i)
but if i == mylist[2], print it but in a different color.

Eg. Mylist = ["David", "holmes, "ngandu"]
Expected output:
David <default printing color>
Holmes <color red>
Ngandu <default printing color>

Answer 1

Your question has the answer itself.

Mylist = ["David", "holmes, "ngandu"]
for name in Mylist:
if name == Mylist[1]:
print(Fore.RED+name)
else:
print(name)

Answer 2

Works fine here.
Try again

myletters = ['a', 'b', 'c', 'b', 'd']

for letter in myletters:
if letter == myletters[1]:
green letter
else:
white letter

Answer 3

Simba nope didn't work the way i want it to.
Example 2.

myletters = ['a', 'b', 'c', 'b', 'd']

Now let's say i want to print out everything in the same order they are, but all 'b's in a different color (eg green):

Expected output:
['a' <in color white>,
'b' <in color GREEN>,
'c' <in color white>,
'b' <in color GREEN>,
'd' <in color white]

Printing it yo way produces:
['a' <in color white>,
'b' <in color GREEN>,
'c' <in color GREEN>,
'b' <in color GREEN>,
'd' <in color GREEN]

Answer 4

Simba screenshot the whole code in console