Why both of them have different output ?

Question

1️⃣
int main()
{
int a, b, c, sum;
float avg;
a=1;
b=6;
c=3;
sum=a+b+c;
avg=sum/3;
cout<<"Sum = "<<sum<<endl;
cout<<"Average = "<<avg;
return 0;
}

2️⃣
int main()
{
int a, b, c;
float sum, avg;
a=1;
b=6;
c=3;
sum=a+b+c;
avg=sum/3;
cout<<"Sum = "<<sum<<endl;
cout<<"Average = "<<avg;
return 0;
}

Why the 1st code prints the integral value of Average and the 2nd one prints the floating value ❓❔

Answer 1

int/int results int
double/int => double
int/double => double
double/double => double

Values are upcasted to higher types in calculations and result is casted back to destination types..

In first, sum is int type so int/int return int data only..

While second sum is of float data type so float/int returns float data type value... Hope it helps..

Answer 2

Jayakrishna🇮🇳 Ok got it....
Thanks 🙏

Answer 3

A͢J Got it... Thanks

Answer 4

Jainil Raval 🇮🇳

sum variable is declared as float so

sum = 1 + 6 + 3 = 10.0

And 10.0 / 3 gives float value

Answer 5

You're welcomeJainil Raval 🇮🇳