[check the description] : does the strinig terminator "\0" included before x since i used i<8, but while printing it, the output

Question

CODE :

int main()
{

char firstName[] = "ANIRBAN";

for (int i = 0; i < 8; i++)
{
printf("%c \t", firstName[i]);
}
printf("%c", 'x');

return 0;
}

OUTPUT :

A N I R B A N x

Answer 1

Print firstName[ i ] as char and integer to find out whether the null terminator was also printed.

printf("%c (%d)\t", firstName[i], firstName[i]);

But as you probably know already, null terminator is non printable character, thus you won't likely see any character prior to the '(0)' printed by '(%d)' format specifier.

And iterating a string past its length is not a safe thing to do, so evade it best you can ...

Answer 2

Glad you got it figured out 👌

Answer 3

Can you point out what's wrong? In this code every character in the array is printed separated by a space character and a tab character (\t). Because of the null-terminator, after 'N' there is double the space (" \t \t"), probably causing the 'x' going on newline because of all the spacing before

Answer 4

@Ipang i tried it....and actually it works ...

this is the output : A (65) N (78) I (73) R (82) B (66) A (65) N (78) (0) x