Cual es el error?, Necesito que cuente cuántos primos hay en los tres número ingresados

Question

#Inicializar
c = 0
i=1
numEntradas = 3
#proceso
print("Ingrese", numEntradas, "Números:")
while i<= numEntradas:
n = int( input("Ingrese número: "))
for r in range(2,n+1):
if n%r== 0 :
c = c + 1
i+=1

if c<2:
print ("En", numEntradas, "números ingresados hay", c,"numeros primos")

Answer 1

some of the problems I see:
• i += 1 is in the 'for' loop, should be in the 'while' loop
• c counts the number of divisors, not the number of primes, and you don't reset it for each n
• you display c in the loop, if you want to display the number of primes (not c, c isn't the number of primes), it should be at the end, outside of any loop.

Btw, you don't need to go to n+1 to determine if n is prime, even for a non-prime you won't find any divisors after n/2 (but if you haven't found a divisor until sqrt(n), sqrt(n) included, then n is prime, you won't find any after). And once you found a divisor, you can break out of the 'for' loop, as it clearly isn't a prime.

Here's how I would have done it:
https://code.sololearn.com/c880u48WSst2

(note that the 'else' I used is for the loop, not for the 'if'; in python, loops can have an 'else' branch that is executed if the loop completes without reaching a break statement)