Why constructor is not called

Question

Please refer code below :

I am not able to observe constructor call... if i remove const from initializer list constructor, normal constructor is getting called... why so ?
https://code.sololearn.com/c2NAi7fyK6LM/?ref=app

Answer 1

If you remove 'const', then the 2nd constructor would be expecting a lvalue reference to an initializer_list. The initializer_list in
test obj{1};
Is not an lvalue, so the 1st constructor that takes an int would be chosen. This reasoning can be proven by passing another argument in the initializer_list
test obj{1, 2};
which would result in a compiler error. Or, by changing the type of parameter in the 2nd constructor to
initializer_list<int>&&