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The given program reads n and finds sum of product of consecutive numbers. If n=7 and numbers are 4,5,2,5,6,4,7 the output shoul

//To find (x1+x2)*x3 +(x2+x3)*x4 + (x3+x4)*x5 #include <stdio.h> int main() { int x[20], sum, i, n; printf("How many numbers"); scanf("%d", &n); for(i=1;i<=n;i++) { printf("Give %d th number", i); scanf("%d", &x[i]); } sum=0; for(i=1;i<=n-2;i++) sum+=sum+(x[i]+x[i+1])*x[i+2]; printf("%d",sum); return 0; }

12th Aug 2022, 9:23 AM
Saurav Singh
Saurav Singh - avatar
1 Respuesta
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#include <stdio.h> int main() { int x[20], sum, i, n; printf("How many numbers"); scanf("%d", &n); for(i=1;i<=n;i++) { printf("Give %d th number", i); scanf("%d", &x[i]); } sum=0; for(i=1;i<=n-4;i++) sum+=sum+((x[i]+x[i+1])*x[i+2]); printf("%d",sum); return 0; }
12th Aug 2022, 9:51 AM
Saurav Singh
Saurav Singh - avatar