[Solved] Returning from recursive functions.

Question

def function(x):
if x == 1:
return x
else:
x -= 1
function(x) # if 'x != 1' returns "None"

x = 10
print(function(x))
>>> None
---------------------------------------------
def function(x):
if x == 1:
return x
else:
x -= 1
return function(x)
# if 'x!=1' returns function(x) recursively to reach "function(1) = 1"

x = 10
print(function(x))
>>> 1
https://code.sololearn.com/cGEdCfDLyeSR/?ref=app

Answer 1

It's a recursive function so
Main call : function(2) returns None.
and function(1) returns 1
Instead of
function(x) write return function(x) in function.

Answer 2

Thank you. Jayakrishna🇮🇳