summartion of even nums

Question

Task:
Find the sum of all even integers in a list of numbers.

Input Format:
The first input denotes the length of the list (N). The next N lines contain the list elements as integers.

Output Format:
An integer that represents the sum of only the even numbers in the list.

Sample Input:
9
1
2
3

5

I have something like this, it works as they said, but I couldn't pass the challenge.
def sum_even(numbers):
sum_nums = 0

for number in numbers:
if number % 2 == 0:
sum_nums += number
elif number % 2 == 1:
sum_nums += 0
return sum_nums

nums = [1,2,3,4,5,6,7,8]
print(sum_even(nums))

Answer 1

Have you created the list first？
Also, elif is redundant code, even else can be omitted.

Answer 2

def sum_even(numbers):
sum_nums = 0
for number in numbers:
if number % 2 == 0: sum_nums += number
return sum_nums

nums = []
n = int(input())
for i in range(n):
nums.append( int(input()) )

print(sum_even(nums))