Find second largest number in list ?------need detailed explanation in this code

Question

n=int(input())
list1=list(map(int,input().split(" ")[:n]))
list1.sort()
c=list1.count(max(list1))
r=list1[len(list1)-(c+1)]
print(r)

Answer 1

NAVEEN VYAS ,

n=int(input()) # define the number of values to input

list1=list(map(int,input().split(" ")[:n])) # input the desired number of values separated by a space. this creates a list of the input numbers as integer values

list1.sort() # sort the list inplace in ascending order

c=list1.count(max(list1)) # count how often the max value exists in the list

r=list1[len(list1)-(c+1)] # pick the second largest number by using a calculated index

print(r) # print the second largest number

Answer 2

The ...[:n] in line 2
is used to specify the number of elements to return in list created using split.

Answer 3

Then y [:n] in second line

Answer 4

What it indicates