Arguments passing to lambda function

Question

Hello dear coders,

Could you please explain how arguments are passed to the following function:

def test(n):
return lambda x: x+n
f = test(230)
print(f(5))

Appreciate your support!

Answer 1

If you try this:

print(type(f))

You see that the type of f is a function. We can also call it a closure, it is an anonymous function returned from test, that is still expecting an argument to work.

When we do test(230) it gives us a function which adds 230 to a number that we pass to it.

Writing
f(5)
is the same as writing
test(230)(5)

Answer 2

Tibor Santa, thank you a lot! You again helped me to understand :)