Why it is not working?

Question

https://code.sololearn.com/cbQ8g2jlbu95/?ref=app

~/.../Download/Termux $ gcc argv_to_string.c -o argv
argv_to_string.c:10:20: warning: passing 'char **' to parameter of type 'const char *const *' discards qualifiers in nested pointer types [-Wincompatible-pointer-types-discards-qualifiers]
argv_to_string(argv, buff, 10);
^~~~ argv_to_string.c:6:42: note: passing argument to parameter here
void argv_to_string(const char * const * , char *, size_t);
^ 1 warning generated. ~/.../Download/Termux $

Answer 1

you need to use the same type
void argv_to_string(char*[], char *, size_t);

Answer 2

Jables have you considered using snprintf()? Or is it a requirement to write your own formatter?

E.g.,
#include <stdio.h>

int main (int argc, char *argv[]) {
char buff[32];
snprintf(buff, 32, "[%s], [%s]", argv[0], argv[1]);
printf("%s", buff);

}

Answer 3

'char**' isn't the same as 'const char* const*'

Answer 4

So how am i move argv to function
Without changing value or address?